HomeAbout UsWhat is Power Factor?Benefits of Power FactorEquipment SpecsBills Before and After
ReferencesGoing GreenContact

Benefit No. 1
60%           70%            80%            90%          100%
600 KW      600 KW      600 KW      600 KW      600 KW
800 KVAR     612 KVAR    450 KVAR     291 KVAR      0 KVAR
1000 KVA      857 KVA       750 KVA       667 KVA       600 KVA
POWER FACTOR

REAL POWER

REACTIVE POWER

TOTAL POWER
60%           70%            80%            90%          100%
360 KW      420 KW      480 KW      540 KW      600 KW
480 KVAR     428 KVAR    360 KVAR     262 KVAR      0 KVAR
600 KVA        600 KVA        600 KVA        600 KVA        600 KVA
POWER FACTOR

REAL POWER

REACTIVE POWER

TOTAL POWER
Less Total Plant KVA for the
Same KW Working Power
Dollar savings are very significant in areas where utility billing is affected by KVA usage.

Example: 600 KW working power vs KVA required
Benefit No. 2
More KW Working Power for the
Same KVA Demand
Released system capacity allows for additional motors, lighting,
etc. to be added without overloading existing distribution equipment.

Example: 600 KW demand vs available KW
Benefit No. 3
Improved Voltage Regulation Due to
Reduced Line Voltage Drop
This benefit will result in more efficient performance of motors and
other electrical equipment.

Example: Fig. 2 depicts what happens to the full load speed and
starting torque of a motor at various levels of rated voltage.
Fig. 2
KW
100
KW
100
KW
100
KW
100
KW
100
KVAR
48
KVAR
75
KVAR
100
KVAR
133
Benefit No. 4
Reduction in Size of Transformers,
Cables and Switchgear in New Installations
- Thus Less Investment
Example: Fig. 3 represents the increasing size of conductors
required to carry the same 100 KW at various power factors.
Fig. 3
KVA-100         KVA-111             KVA-125                    KVA-141                          KVA-167
P.F.- 100%      P.F.- 90%           P.F.- 80%                  P.F.- 70%                         P.F.- 60%
Benefit No. 5
Reduced Power Losses in Distribution Systems
Since These Losses are Proportional
to the Square of the Current.
Since the losses are proportionate to the square of the current, the
following formula applies:
Example: Improve power factor from 65 percent to 90 percent
Per Cent
Speed
Per Cent
Torque and
Full Load Current
Per Cent Rated Voltage
.......................................................................................................................................................................................................................................